3327040141 has 2 divisors, whose sum is σ = 3327040142. Its totient is φ = 3327040140.

The previous prime is 3327040133. The next prime is 3327040147. The reversal of 3327040141 is 1410407233.

3327040141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2782984516 + 544055625 = 52754^2 + 23325^2 .

It is an emirp because it is prime and its reverse (1410407233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3327040141 - 2³ = 3327040133 is a prime.

It is a super-2 number, since 2×3327040141² = 22138392199650599762, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3327040147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1663520070 + 1663520071.

It is an arithmetic number, because the mean of its divisors is an integer number (1663520071).

Almost surely, 2^3327040141 is an apocalyptic number.

It is an amenable number.

3327040141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3327040141 is an equidigital number, since it uses as much as digits as its factorization.

3327040141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 3327040141 is about 57680.5005266078. The cubic root of 3327040141 is about 1492.8609118888.

Adding to 3327040141 its reverse (1410407233), we get a palindrome (4737447374).

The spelling of 3327040141 in words is "three billion, three hundred twenty-seven million, forty thousand, one hundred forty-one".