Base | Representation |
---|---|
bin | 110000011101100000010… |
… | …010100100011110101001 |
3 | 102210100212102022012111200 |
4 | 300131200102210132221 |
5 | 414030240033311040 |
6 | 11025514003514413 |
7 | 462412556410443 |
oct | 60354022443651 |
9 | 12710772265450 |
10 | 3330215135145 |
11 | 1074377697248 |
12 | 459502388a09 |
13 | 1b2065479bb2 |
14 | b727cc85493 |
15 | 5b95e875630 |
hex | 307604a47a9 |
3330215135145 has 24 divisors (see below), whose sum is σ = 5779490563392. Its totient is φ = 1773924688800.
The previous prime is 3330215135123. The next prime is 3330215135189. The reversal of 3330215135145 is 5415315120333.
3330215135145 is a `hidden beast` number, since 3 + 3 + 30 + 21 + 513 + 51 + 45 = 666.
3330215135145 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3330215135145 - 27 = 3330215135017 is a prime.
It is a super-2 number, since 2×33302151351452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 45589141 + ... + 45662130.
It is an arithmetic number, because the mean of its divisors is an integer number (240812106808).
Almost surely, 23330215135145 is an apocalyptic number.
It is an amenable number.
3330215135145 is a deficient number, since it is larger than the sum of its proper divisors (2449275428247).
3330215135145 is a wasteful number, since it uses less digits than its factorization.
3330215135145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91252093 (or 91252090 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
The spelling of 3330215135145 in words is "three trillion, three hundred thirty billion, two hundred fifteen million, one hundred thirty-five thousand, one hundred forty-five".
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