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3330220203041 = 4181224883001
BaseRepresentation
bin110000011101100000100…
…101111001110000100001
3102210100212202211200100112
4300131200211321300201
5414030242332444131
611025514304301105
7462412650445604
oct60354045716041
912710782750315
103330220203041
11107437a538896
12459504011795
131b2066532854
14b727d80433b
155b96002702b
hex30760979c21

3330220203041 has 4 divisors (see below), whose sum is σ = 3411445086084. Its totient is φ = 3248995320000.

The previous prime is 3330220203031. The next prime is 3330220203061. The reversal of 3330220203041 is 1403020220333.

3330220203041 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1269261358225 + 2060958844816 = 1126615^2 + 1435604^2 .

It is a cyclic number.

It is not a de Polignac number, because 3330220203041 - 222 = 3330216008737 is a prime.

It is a super-2 number, since 2×33302202030412 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3330220202998 and 3330220203016.

It is not an unprimeable number, because it can be changed into a prime (3330220203031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40612441460 + ... + 40612441541.

It is an arithmetic number, because the mean of its divisors is an integer number (852861271521).

Almost surely, 23330220203041 is an apocalyptic number.

It is an amenable number.

3330220203041 is a deficient number, since it is larger than the sum of its proper divisors (81224883043).

3330220203041 is an equidigital number, since it uses as much as digits as its factorization.

3330220203041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81224883042.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 3330220203041 its reverse (1403020220333), we get a palindrome (4733240423374).

The spelling of 3330220203041 in words is "three trillion, three hundred thirty billion, two hundred twenty million, two hundred three thousand, forty-one".

Divisors: 1 41 81224883001 3330220203041