Base | Representation |
---|---|
bin | 1001101110001011101… |
… | …00000001010010011111 |
3 | 1011221012012200122020011 |
4 | 10313011310001102133 |
5 | 20433043443330421 |
6 | 413241332304051 |
7 | 33063414415555 |
oct | 4670564012237 |
9 | 1157165618204 |
10 | 334031230111 |
11 | 119730a15167 |
12 | 548a2472027 |
13 | 2566442b267 |
14 | 1224ab0dbd5 |
15 | 8a5017b4e1 |
hex | 4dc5d0149f |
334031230111 has 2 divisors, whose sum is σ = 334031230112. Its totient is φ = 334031230110.
The previous prime is 334031230081. The next prime is 334031230201. The reversal of 334031230111 is 111032130433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 334031230111 - 231 = 331883746463 is a prime.
It is a super-2 number, since 2×3340312301112 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334031230711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167015615055 + 167015615056.
It is an arithmetic number, because the mean of its divisors is an integer number (167015615056).
Almost surely, 2334031230111 is an apocalyptic number.
334031230111 is a deficient number, since it is larger than the sum of its proper divisors (1).
334031230111 is an equidigital number, since it uses as much as digits as its factorization.
334031230111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 334031230111 its reverse (111032130433), we get a palindrome (445063360544).
The spelling of 334031230111 in words is "three hundred thirty-four billion, thirty-one million, two hundred thirty thousand, one hundred eleven".
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