Base | Representation |
---|---|
bin | 11111111001001010… |
… | …101111010100110111 |
3 | 10021101121012222211211 |
4 | 133321022233110313 |
5 | 1030113222110033 |
6 | 23422035342251 |
7 | 2321424442003 |
oct | 377112572467 |
9 | 107347188754 |
10 | 34245113143 |
11 | 135835233aa |
12 | 6778751987 |
13 | 32c9a07a77 |
14 | 192c165703 |
15 | d5666a2cd |
hex | 7f92af537 |
34245113143 has 2 divisors, whose sum is σ = 34245113144. Its totient is φ = 34245113142.
The previous prime is 34245113131. The next prime is 34245113153. The reversal of 34245113143 is 34131154243.
It is a strong prime.
It is an emirp because it is prime and its reverse (34131154243) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34245113143 - 233 = 25655178551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34245113113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17122556571 + 17122556572.
It is an arithmetic number, because the mean of its divisors is an integer number (17122556572).
Almost surely, 234245113143 is an apocalyptic number.
34245113143 is a deficient number, since it is larger than the sum of its proper divisors (1).
34245113143 is an equidigital number, since it uses as much as digits as its factorization.
34245113143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 31.
Adding to 34245113143 its reverse (34131154243), we get a palindrome (68376267386).
The spelling of 34245113143 in words is "thirty-four billion, two hundred forty-five million, one hundred thirteen thousand, one hundred forty-three".
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