3500323 has 2 divisors, whose sum is σ = 3500324. Its totient is φ = 3500322.

The previous prime is 3500297. The next prime is 3500327. The reversal of 3500323 is 3230053.

3500323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (3230053) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3500323 - 2¹³ = 3492131 is a prime.

It is a super-2 number, since 2×3500323² = 24504522208658, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3500297 and 3500306.

It is not a weakly prime, because it can be changed into another prime (3500327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750161 + 1750162.

It is an arithmetic number, because the mean of its divisors is an integer number (1750162).

Almost surely, 2^3500323 is an apocalyptic number.

3500323 is a deficient number, since it is larger than the sum of its proper divisors (1).

3500323 is an equidigital number, since it uses as much as digits as its factorization.

3500323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 16.

The square root of 3500323 is about 1870.9150167766. The cubic root of 3500323 is about 151.8341190132.

Subtracting from 3500323 its product of nonzero digits (270), we obtain a palindrome (3500053).

Adding to 3500323 its reverse (3230053), we get a palindrome (6730376).

The spelling of 3500323 in words is "three million, five hundred thousand, three hundred twenty-three".