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40132327215751 is a prime number
BaseRepresentation
bin10010010000000000010010…
…00110111001001010000111
312021002121112212221001210021
421020000021012321022013
520230012001231401001
6221204311523440011
711311315323603451
oct1110001106711207
9167077485831707
1040132327215751
111187302a513901
124601ab7226007
131951601653024
149ca5b4a992d1
15498e0202aba1
hex2480091b9287

40132327215751 has 2 divisors, whose sum is σ = 40132327215752. Its totient is φ = 40132327215750.

The previous prime is 40132327215727. The next prime is 40132327215811. The reversal of 40132327215751 is 15751272323104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40132327215751 - 27 = 40132327215623 is a prime.

It is a super-2 number, since 2×401323272157512 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40132327215698 and 40132327215707.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132327215451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066163607875 + 20066163607876.

It is an arithmetic number, because the mean of its divisors is an integer number (20066163607876).

Almost surely, 240132327215751 is an apocalyptic number.

40132327215751 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132327215751 is an equidigital number, since it uses as much as digits as its factorization.

40132327215751 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 352800, while the sum is 43.

Adding to 40132327215751 its reverse (15751272323104), we get a palindrome (55883599538855).

The spelling of 40132327215751 in words is "forty trillion, one hundred thirty-two billion, three hundred twenty-seven million, two hundred fifteen thousand, seven hundred fifty-one".