Base | Representation |
---|---|
bin | 111010100001001111111… |
… | …011010101010101100011 |
3 | 112020110000101122220220222 |
4 | 322201033323111111203 |
5 | 1011341342131434021 |
6 | 12315230344353255 |
7 | 563352535630214 |
oct | 72411773252543 |
9 | 15213011586828 |
10 | 4021430343011 |
11 | 131052a654554 |
12 | 54b468a7582b |
13 | 2322b0916c83 |
14 | dc8d159540b |
15 | 6e9175b16ab |
hex | 3a84fed5563 |
4021430343011 has 2 divisors, whose sum is σ = 4021430343012. Its totient is φ = 4021430343010.
The previous prime is 4021430342989. The next prime is 4021430343013. The reversal of 4021430343011 is 1103430341204.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021430343011 - 230 = 4020356601187 is a prime.
It is a super-2 number, since 2×40214303430112 (a number of 26 digits) contains 22 as substring.
Together with 4021430343013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4021430343013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010715171505 + 2010715171506.
It is an arithmetic number, because the mean of its divisors is an integer number (2010715171506).
Almost surely, 24021430343011 is an apocalyptic number.
4021430343011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021430343011 is an equidigital number, since it uses as much as digits as its factorization.
4021430343011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 4021430343011 its reverse (1103430341204), we get a palindrome (5124860684215).
The spelling of 4021430343011 in words is "four trillion, twenty-one billion, four hundred thirty million, three hundred forty-three thousand, eleven".
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