Base | Representation |
---|---|
bin | 111010101100001000001… |
… | …101110100100110100001 |
3 | 112021120011112000021211110 |
4 | 322230020031310212201 |
5 | 1012034303201211001 |
6 | 12324441445533533 |
7 | 564245164326111 |
oct | 72541015644641 |
9 | 15246145007743 |
10 | 4033112132001 |
11 | 1315484723517 |
12 | 5517891142a9 |
13 | 233422b75954 |
14 | dd2bcc1d041 |
15 | 6ed9ce273d6 |
hex | 3ab083749a1 |
4033112132001 has 32 divisors (see below), whose sum is σ = 5684900659200. Its totient is φ = 2536254806400.
The previous prime is 4033112131999. The next prime is 4033112132041. The reversal of 4033112132001 is 1002312113304.
It is not a de Polignac number, because 4033112132001 - 21 = 4033112131999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4033112132041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 160752480 + ... + 160777566.
It is an arithmetic number, because the mean of its divisors is an integer number (177653145600).
Almost surely, 24033112132001 is an apocalyptic number.
It is an amenable number.
4033112132001 is a deficient number, since it is larger than the sum of its proper divisors (1651788527199).
4033112132001 is a wasteful number, since it uses less digits than its factorization.
4033112132001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37149.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 4033112132001 its reverse (1002312113304), we get a palindrome (5035424245305).
The spelling of 4033112132001 in words is "four trillion, thirty-three billion, one hundred twelve million, one hundred thirty-two thousand, one".
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