Base | Representation |
---|---|
bin | 100101101000000011… |
… | …000101100000101011 |
3 | 10212021120101011202221 |
4 | 211220003011200223 |
5 | 1130214442021011 |
6 | 30320515334511 |
7 | 2630105160526 |
oct | 455003054053 |
9 | 125246334687 |
10 | 40400345131 |
11 | 16151a3a293 |
12 | 79b5bb1437 |
13 | 3a6acb4c83 |
14 | 1d53821bbd |
15 | 10b6c17971 |
hex | 9680c582b |
40400345131 has 2 divisors, whose sum is σ = 40400345132. Its totient is φ = 40400345130.
The previous prime is 40400345129. The next prime is 40400345143. The reversal of 40400345131 is 13154300404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40400345131 - 21 = 40400345129 is a prime.
It is a super-2 number, since 2×404003451312 (a number of 22 digits) contains 22 as substring.
Together with 40400345129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 40400345096 and 40400345105.
It is not a weakly prime, because it can be changed into another prime (40400345101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20200172565 + 20200172566.
It is an arithmetic number, because the mean of its divisors is an integer number (20200172566).
Almost surely, 240400345131 is an apocalyptic number.
40400345131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40400345131 is an equidigital number, since it uses as much as digits as its factorization.
40400345131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 40400345131 its reverse (13154300404), we get a palindrome (53554645535).
The spelling of 40400345131 in words is "forty billion, four hundred million, three hundred forty-five thousand, one hundred thirty-one".
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