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BaseRepresentation
bin111010111101000111010…
…010010001010100100001
3112100022020120000200110221
4322331013102101110201
51012334131113211001
612341055313323041
7565462142633554
oct72750722212441
915308216020427
104051350132001
111322193592897
12555218b66481
1323506b4a6923
1410012d0c069b
15705b91441a1
hex3af47491521

4051350132001 has 2 divisors, whose sum is σ = 4051350132002. Its totient is φ = 4051350132000.

The previous prime is 4051350131957. The next prime is 4051350132083. The reversal of 4051350132001 is 1002310531504.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2971831210000 + 1079518922001 = 1723900^2 + 1038999^2 .

It is a cyclic number.

It is not a de Polignac number, because 4051350132001 - 221 = 4051348034849 is a prime.

It is not a weakly prime, because it can be changed into another prime (4051350132601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025675066000 + 2025675066001.

It is an arithmetic number, because the mean of its divisors is an integer number (2025675066001).

Almost surely, 24051350132001 is an apocalyptic number.

It is an amenable number.

4051350132001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4051350132001 is an equidigital number, since it uses as much as digits as its factorization.

4051350132001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 4051350132001 its reverse (1002310531504), we get a palindrome (5053660663505).

The spelling of 4051350132001 in words is "four trillion, fifty-one billion, three hundred fifty million, one hundred thirty-two thousand, one".