4111311131 has 2 divisors, whose sum is σ = 4111311132. Its totient is φ = 4111311130.

The previous prime is 4111311097. The next prime is 4111311167. The reversal of 4111311131 is 1311131114.

4111311131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a m-pointer prime, because the next prime (4111311167) can be obtained adding 4111311131 to its product of digits (36).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4111311131 is a prime.

It is a super-2 number, since 2×4111311131² = 33805758431768998322, which contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (4111319131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055655565 + 2055655566.

It is an arithmetic number, because the mean of its divisors is an integer number (2055655566).

Almost surely, 2^4111311131 is an apocalyptic number.

4111311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111311131 is an equidigital number, since it uses as much as digits as its factorization.

4111311131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 17.

The square root of 4111311131 is about 64119.5066340969. The cubic root of 4111311131 is about 1601.9911578775.

Adding to 4111311131 its reverse (1311131114), we get a palindrome (5422442245).

It can be divided in two parts, 411131113 and 1, that added together give a palindrome (411131114).

The spelling of 4111311131 in words is "four billion, one hundred eleven million, three hundred eleven thousand, one hundred thirty-one".