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41130035 = 526633089
BaseRepresentation
bin1001110011100…
…1100000110011
32212101121210122
42130321200303
541012130120
64025320455
71006412432
oct234714063
985347718
1041130035
1121242671
121193612b
1386a0ccb
145669119
153926a25
hex2739833

41130035 has 8 divisors (see below), whose sum is σ = 49390560. Its totient is φ = 32881024.

The previous prime is 41130013. The next prime is 41130073. The reversal of 41130035 is 53003114.

41130035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 41130035 - 26 = 41129971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41129995 and 41130022.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11771 + ... + 14859.

It is an arithmetic number, because the mean of its divisors is an integer number (6173820).

Almost surely, 241130035 is an apocalyptic number.

41130035 is a deficient number, since it is larger than the sum of its proper divisors (8260525).

41130035 is a wasteful number, since it uses less digits than its factorization.

41130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5757.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 41130035 is about 6413.2702266472. The cubic root of 41130035 is about 345.1858831665.

Adding to 41130035 its reverse (53003114), we get a palindrome (94133149).

The spelling of 41130035 in words is "forty-one million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 2663 3089 13315 15445 8226007 41130035