Search a number
-
+
41200213 = 291420697
BaseRepresentation
bin1001110100101…
…0101001010101
32212112012001211
42131022221111
541021401323
64031021421
71010124145
oct235125125
985465054
1041200213
112129036a
121196a871
1386c6c32
145686925
15393c70d
hex274aa55

41200213 has 4 divisors (see below), whose sum is σ = 42620940. Its totient is φ = 39779488.

The previous prime is 41200171. The next prime is 41200219. The reversal of 41200213 is 31200214.

41200213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11682724 + 29517489 = 3418^2 + 5433^2 .

It is a cyclic number.

It is not a de Polignac number, because 41200213 - 29 = 41199701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41200193 and 41200202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41200219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710320 + ... + 710377.

It is an arithmetic number, because the mean of its divisors is an integer number (10655235).

Almost surely, 241200213 is an apocalyptic number.

It is an amenable number.

41200213 is a deficient number, since it is larger than the sum of its proper divisors (1420727).

41200213 is a wasteful number, since it uses less digits than its factorization.

41200213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1420726.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 41200213 is about 6418.7392064174. The cubic root of 41200213 is about 345.3820957422.

Adding to 41200213 its reverse (31200214), we get a palindrome (72400427).

Subtracting from 41200213 its reverse (31200214), we obtain a palindrome (9999999).

The spelling of 41200213 in words is "forty-one million, two hundred thousand, two hundred thirteen".

Divisors: 1 29 1420697 41200213