Base | Representation |
---|---|
bin | 101110110101110101111110… |
… | …0110111001100010011110111 |
3 | 2000000211202210221002111211002 |
4 | 1131223223330313030103313 |
5 | 413001020342442011210 |
6 | 4020143330051233515 |
7 | 152533331653566662 |
oct | 13553537467142367 |
9 | 2000752727074732 |
10 | 412020455032055 |
11 | 10a311991572871 |
12 | 3a2643a88a889b |
13 | 148b94929844ac |
14 | 73a5c79b1a6d9 |
15 | 32978e6bee4a5 |
hex | 176bafcdcc4f7 |
412020455032055 has 4 divisors (see below), whose sum is σ = 494424546038472. Its totient is φ = 329616364025640.
The previous prime is 412020455032049. The next prime is 412020455032057. The reversal of 412020455032055 is 550230554020214.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 412020455032055 - 212 = 412020455027959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412020455032057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41202045503201 + ... + 41202045503210.
It is an arithmetic number, because the mean of its divisors is an integer number (123606136509618).
Almost surely, 2412020455032055 is an apocalyptic number.
412020455032055 is a deficient number, since it is larger than the sum of its proper divisors (82404091006417).
412020455032055 is an equidigital number, since it uses as much as digits as its factorization.
412020455032055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82404091006416.
The product of its (nonzero) digits is 240000, while the sum is 38.
The spelling of 412020455032055 in words is "four hundred twelve trillion, twenty billion, four hundred fifty-five million, thirty-two thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •