Base | Representation |
---|---|
bin | 1100000001010001111… |
… | …01001111000000010101 |
3 | 1110111000221220002012122 |
4 | 12000220331033000111 |
5 | 23231313011020201 |
6 | 513421553025325 |
7 | 41560424042153 |
oct | 6005075170025 |
9 | 1414027802178 |
10 | 413004001301 |
11 | 14a176aa0011 |
12 | 68062255245 |
13 | 2cc3b7b1378 |
14 | 15dbd2903d3 |
15 | ab2338ae1b |
hex | 6028f4f015 |
413004001301 has 2 divisors, whose sum is σ = 413004001302. Its totient is φ = 413004001300.
The previous prime is 413004001279. The next prime is 413004001313. The reversal of 413004001301 is 103100400314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 373889446225 + 39114555076 = 611465^2 + 197774^2 .
It is a cyclic number.
It is not a de Polignac number, because 413004001301 - 26 = 413004001237 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 413004001301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413004001801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206502000650 + 206502000651.
It is an arithmetic number, because the mean of its divisors is an integer number (206502000651).
Almost surely, 2413004001301 is an apocalyptic number.
It is an amenable number.
413004001301 is a deficient number, since it is larger than the sum of its proper divisors (1).
413004001301 is an equidigital number, since it uses as much as digits as its factorization.
413004001301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 413004001301 its reverse (103100400314), we get a palindrome (516104401615).
The spelling of 413004001301 in words is "four hundred thirteen billion, four million, one thousand, three hundred one".
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