Base | Representation |
---|---|
bin | 1100000011011000011… |
… | …01000101110000100011 |
3 | 1110120221120212002200022 |
4 | 12001230031011300203 |
5 | 23241120322344303 |
6 | 514125534544055 |
7 | 41630403612155 |
oct | 6015415056043 |
9 | 1416846762608 |
10 | 414132231203 |
11 | 14a6a5936919 |
12 | 6831806802b |
13 | 3008b467422 |
14 | 1608905aad5 |
15 | ab8c44b438 |
hex | 606c345c23 |
414132231203 has 4 divisors (see below), whose sum is σ = 423763213368. Its totient is φ = 404501249040.
The previous prime is 414132231173. The next prime is 414132231263. The reversal of 414132231203 is 302132231414.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 414132231203 - 222 = 414128036899 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (414132231263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4815491018 + ... + 4815491103.
It is an arithmetic number, because the mean of its divisors is an integer number (105940803342).
Almost surely, 2414132231203 is an apocalyptic number.
414132231203 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
414132231203 is a deficient number, since it is larger than the sum of its proper divisors (9630982165).
414132231203 is an equidigital number, since it uses as much as digits as its factorization.
414132231203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9630982164.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 414132231203 its reverse (302132231414), we get a palindrome (716264462617).
The spelling of 414132231203 in words is "four hundred fourteen billion, one hundred thirty-two million, two hundred thirty-one thousand, two hundred three".
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