Base | Representation |
---|---|
bin | 10011010010010101001111… |
… | …10110101100010011100111 |
3 | 12120011111001000222001102210 |
4 | 21221022213312230103213 |
5 | 21024331342220304111 |
6 | 230111254245134503 |
7 | 11635055061135513 |
oct | 1151124766542347 |
9 | 176144030861383 |
10 | 42411323213031 |
11 | 125715a5324853 |
12 | 490b7223ba433 |
13 | 1a884a832c306 |
14 | a68a0ccd5143 |
15 | 4d83387290a6 |
hex | 2692a7dac4e7 |
42411323213031 has 64 divisors (see below), whose sum is σ = 63107176204800. Its totient is φ = 25220427724800.
The previous prime is 42411323213029. The next prime is 42411323213033. The reversal of 42411323213031 is 13031232311424.
It is an interprime number because it is at equal distance from previous prime (42411323213029) and next prime (42411323213033).
It is not a de Polignac number, because 42411323213031 - 21 = 42411323213029 is a prime.
It is a super-2 number, since 2×424113232130312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 42411323213031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42411323213033) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 153503371 + ... + 153779411.
It is an arithmetic number, because the mean of its divisors is an integer number (986049628200).
Almost surely, 242411323213031 is an apocalyptic number.
42411323213031 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
42411323213031 is a deficient number, since it is larger than the sum of its proper divisors (20695852991769).
42411323213031 is a wasteful number, since it uses less digits than its factorization.
42411323213031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 278400.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 42411323213031 its reverse (13031232311424), we get a palindrome (55442555524455).
The spelling of 42411323213031 in words is "forty-two trillion, four hundred eleven billion, three hundred twenty-three million, two hundred thirteen thousand, thirty-one".
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