Base | Representation |
---|---|
bin | 1100010111101000001… |
… | …11111100111000111011 |
3 | 1111122000011012222202122 |
4 | 12023310013330320323 |
5 | 23430401121120443 |
6 | 523124330551455 |
7 | 42463646546456 |
oct | 6136407747073 |
9 | 1448004188678 |
10 | 425002520123 |
11 | 15427392a875 |
12 | 6a45059858b |
13 | 3110154794c |
14 | 167daa0449d |
15 | b0c6917968 |
hex | 62f41fce3b |
425002520123 has 2 divisors, whose sum is σ = 425002520124. Its totient is φ = 425002520122.
The previous prime is 425002520119. The next prime is 425002520141. The reversal of 425002520123 is 321025200524.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 425002520123 - 22 = 425002520119 is a prime.
It is a super-2 number, since 2×4250025201232 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 425002520092 and 425002520101.
It is not a weakly prime, because it can be changed into another prime (425002522123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 212501260061 + 212501260062.
It is an arithmetic number, because the mean of its divisors is an integer number (212501260062).
Almost surely, 2425002520123 is an apocalyptic number.
425002520123 is a deficient number, since it is larger than the sum of its proper divisors (1).
425002520123 is an equidigital number, since it uses as much as digits as its factorization.
425002520123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 26.
Adding to 425002520123 its reverse (321025200524), we get a palindrome (746027720647).
The spelling of 425002520123 in words is "four hundred twenty-five billion, two million, five hundred twenty thousand, one hundred twenty-three".
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