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4301141223149 is a prime number
BaseRepresentation
bin111110100101101111111…
…111101010011011101101
3120020011222221000212112022
4332211233333222123231
51030432214123120044
613051530023315525
7622514201112611
oct76455777523355
916204887025468
104301141223149
1114091160a97a1
1259570b5abba5
132527991ac4c4
1410c267c71341
1576d389443ee
hex3e96ffea6ed

4301141223149 has 2 divisors, whose sum is σ = 4301141223150. Its totient is φ = 4301141223148.

The previous prime is 4301141223101. The next prime is 4301141223157. The reversal of 4301141223149 is 9413221411034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3676353733924 + 624787489225 = 1917382^2 + 790435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4301141223149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4301141423149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150570611574 + 2150570611575.

It is an arithmetic number, because the mean of its divisors is an integer number (2150570611575).

Almost surely, 24301141223149 is an apocalyptic number.

It is an amenable number.

4301141223149 is a deficient number, since it is larger than the sum of its proper divisors (1).

4301141223149 is an equidigital number, since it uses as much as digits as its factorization.

4301141223149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 4301141223149 in words is "four trillion, three hundred one billion, one hundred forty-one million, two hundred twenty-three thousand, one hundred forty-nine".