Base | Representation |
---|---|
bin | 10011100111010000010100… |
… | …10001110100110010001001 |
3 | 12122201012200011111112220011 |
4 | 21303220022101310302021 |
5 | 21123121204402444431 |
6 | 231421431143031521 |
7 | 12041025256231030 |
oct | 1163501221646211 |
9 | 178635604445804 |
10 | 43130234031241 |
11 | 1281947a787025 |
12 | 4a06b1813b5a1 |
13 | 1b0b2186102c6 |
14 | a9172b99b717 |
15 | 4ebdb2b01cb1 |
hex | 273a0a474c89 |
43130234031241 has 32 divisors (see below), whose sum is σ = 52306722404352. Its totient is φ = 34717139278080.
The previous prime is 43130234031103. The next prime is 43130234031259. The reversal of 43130234031241 is 14213043203134.
It is a de Polignac number, because none of the positive numbers 2k-43130234031241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43130234031281) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1506402996 + ... + 1506431626.
It is an arithmetic number, because the mean of its divisors is an integer number (1634585075136).
Almost surely, 243130234031241 is an apocalyptic number.
It is an amenable number.
43130234031241 is a deficient number, since it is larger than the sum of its proper divisors (9176488373111).
43130234031241 is a wasteful number, since it uses less digits than its factorization.
43130234031241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56229.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 43130234031241 its reverse (14213043203134), we get a palindrome (57343277234375).
The spelling of 43130234031241 in words is "forty-three trillion, one hundred thirty billion, two hundred thirty-four million, thirty-one thousand, two hundred forty-one".
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