Base | Representation |
---|---|
bin | 101000001011000011… |
… | …100010111110100011 |
3 | 11010100011101202120112 |
4 | 220023003202332203 |
5 | 1201320044331120 |
6 | 31452132001535 |
7 | 3054633512513 |
oct | 501303427643 |
9 | 133304352515 |
10 | 43135152035 |
11 | 1732573a188 |
12 | 8439a602ab |
13 | 40b5767601 |
14 | 2132b15843 |
15 | 11c6d75bc5 |
hex | a0b0e2fa3 |
43135152035 has 4 divisors (see below), whose sum is σ = 51762182448. Its totient is φ = 34508121624.
The previous prime is 43135152023. The next prime is 43135152091. The reversal of 43135152035 is 53025153134.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53025153134 = 2 ⋅26512576567.
It is a cyclic number.
It is not a de Polignac number, because 43135152035 - 26 = 43135151971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43135151992 and 43135152010.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4313515199 + ... + 4313515208.
It is an arithmetic number, because the mean of its divisors is an integer number (12940545612).
Almost surely, 243135152035 is an apocalyptic number.
43135152035 is a deficient number, since it is larger than the sum of its proper divisors (8627030413).
43135152035 is an equidigital number, since it uses as much as digits as its factorization.
43135152035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8627030412.
The product of its (nonzero) digits is 27000, while the sum is 32.
The spelling of 43135152035 in words is "forty-three billion, one hundred thirty-five million, one hundred fifty-two thousand, thirty-five".
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