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4331231130041 is a prime number
BaseRepresentation
bin111111000001110001011…
…111100011000110111001
3120100001122221111111222022
4333001301133203012321
51031430330132130131
613113423510404225
7624630642105644
oct77016137430671
916301587444868
104331231130041
11141a957070142
1259b508660675
1325558309303a
1410d8c0200a5b
15779ea3cc37b
hex3f0717e31b9

4331231130041 has 2 divisors, whose sum is σ = 4331231130042. Its totient is φ = 4331231130040.

The previous prime is 4331231129989. The next prime is 4331231130067. The reversal of 4331231130041 is 1400311321334.

It is an a-pointer prime, because the next prime (4331231130067) can be obtained adding 4331231130041 to its sum of digits (26).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3753631130041 + 577600000000 = 1937429^2 + 760000^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331231130041 is a prime.

It is not a weakly prime, because it can be changed into another prime (4331231130091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165615565020 + 2165615565021.

It is an arithmetic number, because the mean of its divisors is an integer number (2165615565021).

Almost surely, 24331231130041 is an apocalyptic number.

It is an amenable number.

4331231130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331231130041 is an equidigital number, since it uses as much as digits as its factorization.

4331231130041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 4331231130041 its reverse (1400311321334), we get a palindrome (5731542451375).

The spelling of 4331231130041 in words is "four trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred thirty thousand, forty-one".