Base | Representation |
---|---|
bin | 111111000001111000001… |
… | …110100011001010001001 |
3 | 120100001221211002201020222 |
4 | 333001320032203022021 |
5 | 1031431043043124223 |
6 | 13113443024155425 |
7 | 624633513340106 |
oct | 77017016431211 |
9 | 16301854081228 |
10 | 4331344114313 |
11 | 141aa0491a977 |
12 | 59b53a468b75 |
13 | 2555a0601838 |
14 | 10d8d1211aad |
15 | 77a052990c8 |
hex | 3f0783a3289 |
4331344114313 has 32 divisors (see below), whose sum is σ = 4689578678400. Its totient is φ = 3992276445696.
The previous prime is 4331344114217. The next prime is 4331344114327. The reversal of 4331344114313 is 3134114431334.
It is not a de Polignac number, because 4331344114313 - 224 = 4331327337097 is a prime.
It is a super-2 number, since 2×43313441143132 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4331344114343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12557981 + ... + 12898277.
It is an arithmetic number, because the mean of its divisors is an integer number (146549333700).
Almost surely, 24331344114313 is an apocalyptic number.
4331344114313 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4331344114313 is a deficient number, since it is larger than the sum of its proper divisors (358234564087).
4331344114313 is a wasteful number, since it uses less digits than its factorization.
4331344114313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 340601.
The product of its digits is 62208, while the sum is 35.
Adding to 4331344114313 its reverse (3134114431334), we get a palindrome (7465458545647).
The spelling of 4331344114313 in words is "four trillion, three hundred thirty-one billion, three hundred forty-four million, one hundred fourteen thousand, three hundred thirteen".
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