Base | Representation |
---|---|
bin | 111111000010100010011… |
… | …100010000100011110101 |
3 | 120100010210011202212122120 |
4 | 333002202130100203311 |
5 | 1031434020400214341 |
6 | 13114041204150153 |
7 | 624660203265540 |
oct | 77024234204365 |
9 | 16303704685576 |
10 | 4332052351221 |
11 | 1420238685831 |
12 | 59b6b7698359 |
13 | 25568426612a |
14 | 10d95b2d1857 |
15 | 77a47547066 |
hex | 3f0a27108f5 |
4332052351221 has 32 divisors (see below), whose sum is σ = 6888501024768. Its totient is φ = 2367737486400.
The previous prime is 4332052351117. The next prime is 4332052351241. The reversal of 4332052351221 is 1221532502334.
4332052351221 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4332052351221 - 211 = 4332052349173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4332052351241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13291015 + ... + 13613051.
It is an arithmetic number, because the mean of its divisors is an integer number (215265657024).
Almost surely, 24332052351221 is an apocalyptic number.
It is an amenable number.
4332052351221 is a deficient number, since it is larger than the sum of its proper divisors (2556448673547).
4332052351221 is a wasteful number, since it uses less digits than its factorization.
4332052351221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 349921.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 4332052351221 its reverse (1221532502334), we get a palindrome (5553584853555).
The spelling of 4332052351221 in words is "four trillion, three hundred thirty-two billion, fifty-two million, three hundred fifty-one thousand, two hundred twenty-one".
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