4333141140241 has 2 divisors, whose sum is σ = 4333141140242. Its totient is φ = 4333141140240.

The previous prime is 4333141140221. The next prime is 4333141140271. The reversal of 4333141140241 is 1420411413334.

4333141140241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4330727481600 + 2413658641 = 2081040^2 + 49129^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4333141140241 is a prime.

It is a super-2 number, since 2×4333141140241² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4333141140221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166570570120 + 2166570570121.

It is an arithmetic number, because the mean of its divisors is an integer number (2166570570121).

Almost surely, 2^{4333141140241} is an apocalyptic number.

It is an amenable number.

4333141140241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4333141140241 is an equidigital number, since it uses as much as digits as its factorization.

4333141140241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4333141140241 its reverse (1420411413334), we get a palindrome (5753552553575).

The spelling of 4333141140241 in words is "four trillion, three hundred thirty-three billion, one hundred forty-one million, one hundred forty thousand, two hundred forty-one".