Base | Representation |
---|---|
bin | 111111000101011010100… |
… | …110110101100100110111 |
3 | 120100102202111202000002120 |
4 | 333011122212311210313 |
5 | 1032011332341211043 |
6 | 13115311541011023 |
7 | 625126602062043 |
oct | 77053246654467 |
9 | 16312674660076 |
10 | 4335142132023 |
11 | 142158379788a |
12 | 5a021a3b3a73 |
13 | 255a574238b1 |
14 | 10db717c9023 |
15 | 77b78922983 |
hex | 3f15a9b5937 |
4335142132023 has 4 divisors (see below), whose sum is σ = 5780189509368. Its totient is φ = 2890094754680.
The previous prime is 4335142131953. The next prime is 4335142132039. The reversal of 4335142132023 is 3202312415334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4335142132023 - 221 = 4335140034871 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4335142137023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 722523688668 + ... + 722523688673.
It is an arithmetic number, because the mean of its divisors is an integer number (1445047377342).
Almost surely, 24335142132023 is an apocalyptic number.
4335142132023 is a deficient number, since it is larger than the sum of its proper divisors (1445047377345).
4335142132023 is a wasteful number, since it uses less digits than its factorization.
4335142132023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1445047377344.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 4335142132023 its reverse (3202312415334), we get a palindrome (7537454547357).
The spelling of 4335142132023 in words is "four trillion, three hundred thirty-five billion, one hundred forty-two million, one hundred thirty-two thousand, twenty-three".
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