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4351145501413 is a prime number
BaseRepresentation
bin111111010100010100011…
…110110110001011100101
3120101222001210220101211101
4333110110132312023211
51032242121222021123
613130515540440101
7626234304344464
oct77242436661345
916358053811741
104351145501413
1114283462240a7
125a33459a9031
13257407ab9639
1411084cd969db
15782b3881aad
hex3f5147b62e5

4351145501413 has 2 divisors, whose sum is σ = 4351145501414. Its totient is φ = 4351145501412.

The previous prime is 4351145501377. The next prime is 4351145501431. The reversal of 4351145501413 is 3141055411534.

Together with next prime (4351145501431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4341859866369 + 9285635044 = 2083713^2 + 96362^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4351145501413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4351145901413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175572750706 + 2175572750707.

It is an arithmetic number, because the mean of its divisors is an integer number (2175572750707).

Almost surely, 24351145501413 is an apocalyptic number.

It is an amenable number.

4351145501413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4351145501413 is an equidigital number, since it uses as much as digits as its factorization.

4351145501413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 37.

The spelling of 4351145501413 in words is "four trillion, three hundred fifty-one billion, one hundred forty-five million, five hundred one thousand, four hundred thirteen".