Base | Representation |
---|---|
bin | 10100001001101000010000… |
… | …00001001001111000111100 |
3 | 12210220010020112021122001202 |
4 | 22010310020001021320330 |
5 | 21301444031400110322 |
6 | 234124200305155032 |
7 | 12222246423255224 |
oct | 1204641001117074 |
9 | 183803215248052 |
10 | 44311312113212 |
11 | 1313435a549031 |
12 | 4b779b492ba78 |
13 | 1b957009988c1 |
14 | ad2971075084 |
15 | 51c98b528292 |
hex | 284d08049e3c |
44311312113212 has 24 divisors (see below), whose sum is σ = 81803164452240. Its totient is φ = 20944038360960.
The previous prime is 44311312113209. The next prime is 44311312113217. The reversal of 44311312113212 is 21231121311344.
It is a super-2 number, since 2×443113121132122 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44311312113217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 632333273 + ... + 632403344.
It is an arithmetic number, because the mean of its divisors is an integer number (3408465185510).
Almost surely, 244311312113212 is an apocalyptic number.
It is an amenable number.
44311312113212 is a deficient number, since it is larger than the sum of its proper divisors (37491852339028).
44311312113212 is a wasteful number, since it uses less digits than its factorization.
44311312113212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1264737101 (or 1264737099 counting only the distinct ones).
The product of its digits is 3456, while the sum is 29.
Adding to 44311312113212 its reverse (21231121311344), we get a palindrome (65542433424556).
The spelling of 44311312113212 in words is "forty-four trillion, three hundred eleven billion, three hundred twelve million, one hundred thirteen thousand, two hundred twelve".
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