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45403675244441 is a prime number
BaseRepresentation
bin10100101001011010111011…
…11011110011011110011001
312221202112211012020021021222
422110231131323303132121
521422343211330310231
6240322054354141425
712364210253550233
oct1224553573633631
9187675735207258
1045403675244441
1113515655005528
125113652b81875
131c44718533ac7
14b2d79a19d253
1553b0c180d27b
hex294b5def3799

45403675244441 has 2 divisors, whose sum is σ = 45403675244442. Its totient is φ = 45403675244440.

The previous prime is 45403675244381. The next prime is 45403675244443. The reversal of 45403675244441 is 14444257630454.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44377447489600 + 1026227754841 = 6661640^2 + 1013029^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-45403675244441 is a prime.

It is a super-2 number, since 2×454036752444412 (a number of 28 digits) contains 22 as substring.

Together with 45403675244443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (45403675244443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22701837622220 + 22701837622221.

It is an arithmetic number, because the mean of its divisors is an integer number (22701837622221).

Almost surely, 245403675244441 is an apocalyptic number.

It is an amenable number.

45403675244441 is a deficient number, since it is larger than the sum of its proper divisors (1).

45403675244441 is an equidigital number, since it uses as much as digits as its factorization.

45403675244441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25804800, while the sum is 53.

The spelling of 45403675244441 in words is "forty-five trillion, four hundred three billion, six hundred seventy-five million, two hundred forty-four thousand, four hundred forty-one".