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47373472699381 is a prime number
BaseRepresentation
bin10101100010101111111110…
…00000110001001111110101
320012201212012202122212022001
422301113333000301033311
522202131333002340011
6244431023425535301
712656422546632133
oct1261277700611765
9205655182585261
1047373472699381
1114104a82351174
1253913681a4531
1320583b776752a
14b9ac6175c753
1557245d0037c1
hex2b15ff0313f5

47373472699381 has 2 divisors, whose sum is σ = 47373472699382. Its totient is φ = 47373472699380.

The previous prime is 47373472699321. The next prime is 47373472699403. The reversal of 47373472699381 is 18399627437374.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43617372879025 + 3756099820356 = 6604345^2 + 1938066^2 .

It is a cyclic number.

It is not a de Polignac number, because 47373472699381 - 27 = 47373472699253 is a prime.

It is a super-2 number, since 2×473734726993812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47373472699321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23686736349690 + 23686736349691.

It is an arithmetic number, because the mean of its divisors is an integer number (23686736349691).

Almost surely, 247373472699381 is an apocalyptic number.

It is an amenable number.

47373472699381 is a deficient number, since it is larger than the sum of its proper divisors (1).

47373472699381 is an equidigital number, since it uses as much as digits as its factorization.

47373472699381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152216576, while the sum is 73.

The spelling of 47373472699381 in words is "forty-seven trillion, three hundred seventy-three billion, four hundred seventy-two million, six hundred ninety-nine thousand, three hundred eighty-one".