Base | Representation |
---|---|
bin | 11100110010111… |
… | …110100010111101 |
3 | 1020200002022111201 |
4 | 130302332202331 |
5 | 1442140003222 |
6 | 115535015501 |
7 | 14654332654 |
oct | 3462764275 |
9 | 1220068451 |
10 | 483125437 |
11 | 228791323 |
12 | 11596a591 |
13 | 79127452 |
14 | 4824219b |
15 | 2c633427 |
hex | 1ccbe8bd |
483125437 has 4 divisors (see below), whose sum is σ = 487640736. Its totient is φ = 478610140.
The previous prime is 483125417. The next prime is 483125459. The reversal of 483125437 is 734521384.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 483125437 - 227 = 348907709 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 483125396 and 483125405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (483125417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2257489 + ... + 2257702.
It is an arithmetic number, because the mean of its divisors is an integer number (121910184).
Almost surely, 2483125437 is an apocalyptic number.
It is an amenable number.
483125437 is a deficient number, since it is larger than the sum of its proper divisors (4515299).
483125437 is a wasteful number, since it uses less digits than its factorization.
483125437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4515298.
The product of its digits is 80640, while the sum is 37.
The square root of 483125437 is about 21980.1145811390. The cubic root of 483125437 is about 784.6692519847.
The spelling of 483125437 in words is "four hundred eighty-three million, one hundred twenty-five thousand, four hundred thirty-seven".
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