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4834629294097 is a prime number
BaseRepresentation
bin100011001011010011001…
…0111001001100000010001
3122010012000121221211221211
41012112212113021200101
51113202310044402342
614140555324220121
71006201422645211
oct106264627114021
918105017854854
104834629294097
1115a439a21a589
12660b9769a641
13290b99243075
14129dd6874241
1585b5e503c17
hex465a65c9811

4834629294097 has 2 divisors, whose sum is σ = 4834629294098. Its totient is φ = 4834629294096.

The previous prime is 4834629294017. The next prime is 4834629294119. The reversal of 4834629294097 is 7904929264384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4788608747521 + 46020546576 = 2188289^2 + 214524^2 .

It is a cyclic number.

It is not a de Polignac number, because 4834629294097 - 219 = 4834628769809 is a prime.

It is a super-2 number, since 2×48346292940972 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4834629294017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2417314647048 + 2417314647049.

It is an arithmetic number, because the mean of its divisors is an integer number (2417314647049).

Almost surely, 24834629294097 is an apocalyptic number.

It is an amenable number.

4834629294097 is a deficient number, since it is larger than the sum of its proper divisors (1).

4834629294097 is an equidigital number, since it uses as much as digits as its factorization.

4834629294097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 188116992, while the sum is 67.

The spelling of 4834629294097 in words is "four trillion, eight hundred thirty-four billion, six hundred twenty-nine million, two hundred ninety-four thousand, ninety-seven".