49999995000000 has 672 divisors, whose sum is σ = 179932742496000. Its totient is φ = 13274688000000.

The previous prime is 49999994999989. The next prime is 49999995000023. The reversal of 49999995000000 is 59999994.

49999995000000 is a `hidden beast` number, since 499 + 9 + 9 + 99 + 50 + 0 + 0 + 0 + 0 + 0 = 666.

49999995000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

49999995000000 is a nontrivial binomial coefficient, being equal to C(10000000, 2).

It is a junction number, because it is equal to n+sod(n) for n = 49999994999892 and 49999994999901.

It is a congruent number.

It is an unprimeable number.

It is a Kaprekar number, because its square (2499999500000025000000000000) can be partitioned into two parts whose sum is 49999995000000.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 10754997676 + ... + 10755002324.

Almost surely, 2^{49999995000000} is an apocalyptic number.

49999995000000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

49999995000000 is the 9999999-th triangular number and also the 5000000-th hexagonal number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49999995000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (89966371248000).

49999995000000 is an abundant number, since it is smaller than the sum of its proper divisors (129932747496000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49999995000000 is an frugal number, since it uses more digits than its factorization.

49999995000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4941 (or 4898 counting only the distinct ones).

The product of its (nonzero) digits is 10628820, while the sum is 63.

It can be divided in two parts, 4999999 and 5000000, that added together give a palindrome (9999999).

The spelling of 49999995000000 in words is "forty-nine trillion, nine hundred ninety-nine billion, nine hundred ninety-five million", and thus it is an aban number.