Base | Representation |
---|---|
bin | 10110111000110000110001… |
… | …01011001101011000000011 |
3 | 20121012101112110001102122122 |
4 | 23130120120223031120003 |
5 | 23044041431213122231 |
6 | 255012430015554455 |
7 | 13413065406624422 |
oct | 1334303053153003 |
9 | 217171473042578 |
10 | 50328840754691 |
11 | 15044383599244 |
12 | 578a096b2ba2b |
13 | 2210cb26c16b5 |
14 | c5dd00c332b9 |
15 | 5c427e2ac77b |
hex | 2dc618acd603 |
50328840754691 has 2 divisors, whose sum is σ = 50328840754692. Its totient is φ = 50328840754690.
The previous prime is 50328840754679. The next prime is 50328840754837. The reversal of 50328840754691 is 19645704882305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50328840754691 - 214 = 50328840738307 is a prime.
It is a super-3 number, since 3×503288407546913 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50328800754691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25164420377345 + 25164420377346.
It is an arithmetic number, because the mean of its divisors is an integer number (25164420377346).
It is a 1-persistent number, because it is pandigital, but 2⋅50328840754691 = 100657681509382 is not.
Almost surely, 250328840754691 is an apocalyptic number.
50328840754691 is a deficient number, since it is larger than the sum of its proper divisors (1).
50328840754691 is an equidigital number, since it uses as much as digits as its factorization.
50328840754691 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58060800, while the sum is 62.
The spelling of 50328840754691 in words is "fifty trillion, three hundred twenty-eight billion, eight hundred forty million, seven hundred fifty-four thousand, six hundred ninety-one".
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