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5034311301055 = 51277928049293
BaseRepresentation
bin100100101000010010001…
…0101100011011110111111
3122211021102210212211000011
41021100210111203132333
51124440232143113210
614412421454444051
71026500633002621
oct111204425433677
918737383784004
105034311301055
111671048537913
12693824803627
132a696c70467a
1413593a61ac11
158ae49ab2d8a
hex494245637bf

5034311301055 has 8 divisors (see below), whose sum is σ = 6088741857792. Its totient is φ = 3995736843168.

The previous prime is 5034311300959. The next prime is 5034311301067. The reversal of 5034311301055 is 5501031134305.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5034311301055 - 217 = 5034311169983 is a prime.

It is a super-2 number, since 2×50343113010552 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3964024012 + ... + 3964025281.

It is an arithmetic number, because the mean of its divisors is an integer number (761092732224).

Almost surely, 25034311301055 is an apocalyptic number.

5034311301055 is a deficient number, since it is larger than the sum of its proper divisors (1054430556737).

5034311301055 is a wasteful number, since it uses less digits than its factorization.

5034311301055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7928049425.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 5034311301055 in words is "five trillion, thirty-four billion, three hundred eleven million, three hundred one thousand, fifty-five".