Base | Representation |
---|---|
bin | 10110111111001101101111… |
… | …00100110111110100111011 |
3 | 20121222120210202010012021211 |
4 | 23133212313210313310323 |
5 | 23111210011300044003 |
6 | 255302334014343551 |
7 | 13435104516266521 |
oct | 1337466744676473 |
9 | 217876722105254 |
10 | 50550550003003 |
11 | 1511a405698a76 |
12 | 5805050ababb7 |
13 | 2228b8655241b |
14 | c6a93420c311 |
15 | 5c9e0857b96d |
hex | 2df9b7937d3b |
50550550003003 has 2 divisors, whose sum is σ = 50550550003004. Its totient is φ = 50550550003002.
The previous prime is 50550550002983. The next prime is 50550550003021. The reversal of 50550550003003 is 30030005505505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50550550003003 - 225 = 50550516448571 is a prime.
It is a super-3 number, since 3×505505500030033 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50550550033003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25275275001501 + 25275275001502.
It is an arithmetic number, because the mean of its divisors is an integer number (25275275001502).
Almost surely, 250550550003003 is an apocalyptic number.
50550550003003 is a deficient number, since it is larger than the sum of its proper divisors (1).
50550550003003 is an equidigital number, since it uses as much as digits as its factorization.
50550550003003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28125, while the sum is 31.
Adding to 50550550003003 its reverse (30030005505505), we get a palindrome (80580555508508).
The spelling of 50550550003003 in words is "fifty trillion, five hundred fifty billion, five hundred fifty million, three thousand, three".
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