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5073685167433 is a prime number
BaseRepresentation
bin100100111010100111100…
…1100111011110101001001
3122222001001211202110122111
41021311033030323311021
51131111401400324213
614442452505222321
71032363435231151
oct111651714736511
918861054673574
105073685167433
111686813008453
1269b392a919a1
132aa5a5b3b15c
141377d399b761
158bea1618a3d
hex49d4f33bd49

5073685167433 has 2 divisors, whose sum is σ = 5073685167434. Its totient is φ = 5073685167432.

The previous prime is 5073685167413. The next prime is 5073685167451. The reversal of 5073685167433 is 3347615863705.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2950160065609 + 2123525101824 = 1717603^2 + 1457232^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5073685167433 is a prime.

It is not a weakly prime, because it can be changed into another prime (5073685167403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2536842583716 + 2536842583717.

It is an arithmetic number, because the mean of its divisors is an integer number (2536842583717).

Almost surely, 25073685167433 is an apocalyptic number.

It is an amenable number.

5073685167433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5073685167433 is an equidigital number, since it uses as much as digits as its factorization.

5073685167433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38102400, while the sum is 58.

The spelling of 5073685167433 in words is "five trillion, seventy-three billion, six hundred eighty-five million, one hundred sixty-seven thousand, four hundred thirty-three".