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BaseRepresentation
bin100101001010101000100…
…1111011111101001110011
3200002022211211001212020021
41022111101033133221303
51132142321224200001
614510341423224311
71035021651135145
oct112252117375163
920068754055207
105108079131251
11169a362558538
126a5b91448097
132b08c7631935
141393377ccc95
158cd15d87ba1
hex4a5513dfa73

5108079131251 has 2 divisors, whose sum is σ = 5108079131252. Its totient is φ = 5108079131250.

The previous prime is 5108079131231. The next prime is 5108079131263. The reversal of 5108079131251 is 1521319708015.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5108079131251 - 231 = 5105931647603 is a prime.

It is a super-2 number, since 2×51080791312512 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5108079131198 and 5108079131207.

It is not a weakly prime, because it can be changed into another prime (5108079131231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2554039565625 + 2554039565626.

It is an arithmetic number, because the mean of its divisors is an integer number (2554039565626).

Almost surely, 25108079131251 is an apocalyptic number.

5108079131251 is a deficient number, since it is larger than the sum of its proper divisors (1).

5108079131251 is an equidigital number, since it uses as much as digits as its factorization.

5108079131251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600, while the sum is 43.

The spelling of 5108079131251 in words is "five trillion, one hundred eight billion, seventy-nine million, one hundred thirty-one thousand, two hundred fifty-one".