Base | Representation |
---|---|
bin | 10111001110110100000011… |
… | …10010010110110011110101 |
3 | 20200212211020022100212022101 |
4 | 23213122001302112303311 |
5 | 23144000142212330432 |
6 | 300352453403102101 |
7 | 13521610360213021 |
oct | 1347320162266365 |
9 | 220784208325271 |
10 | 51086518480117 |
11 | 1530674194a70a |
12 | 5890aab811931 |
13 | 2267590444b43 |
14 | c8885a401381 |
15 | 5d8d26c964e7 |
hex | 2e7681c96cf5 |
51086518480117 has 2 divisors, whose sum is σ = 51086518480118. Its totient is φ = 51086518480116.
The previous prime is 51086518480099. The next prime is 51086518480157. The reversal of 51086518480117 is 71108481568015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42227240066001 + 8859278414116 = 6498249^2 + 2976454^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51086518480117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51086518480157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25543259240058 + 25543259240059.
It is an arithmetic number, because the mean of its divisors is an integer number (25543259240059).
Almost surely, 251086518480117 is an apocalyptic number.
It is an amenable number.
51086518480117 is a deficient number, since it is larger than the sum of its proper divisors (1).
51086518480117 is an equidigital number, since it uses as much as digits as its factorization.
51086518480117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2150400, while the sum is 55.
The spelling of 51086518480117 in words is "fifty-one trillion, eighty-six billion, five hundred eighteen million, four hundred eighty thousand, one hundred seventeen".
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