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5110147 = 7730021
BaseRepresentation
bin10011011111100110000011
3100121121210201
4103133212003
52302011042
6301310031
761302250
oct23374603
910547721
105110147
112980369
121865317
13109bc73
14970427
156ae1b7
hex4df983

5110147 has 4 divisors (see below), whose sum is σ = 5840176. Its totient is φ = 4380120.

The previous prime is 5110141. The next prime is 5110159. The reversal of 5110147 is 7410115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7410115 = 51482023.

It is a cyclic number.

It is not a de Polignac number, because 5110147 - 27 = 5110019 is a prime.

It is a super-3 number, since 3×51101473 (a number of 21 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5110141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365004 + ... + 365017.

It is an arithmetic number, because the mean of its divisors is an integer number (1460044).

Almost surely, 25110147 is an apocalyptic number.

5110147 is a deficient number, since it is larger than the sum of its proper divisors (730029).

5110147 is an equidigital number, since it uses as much as digits as its factorization.

5110147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 730028.

The product of its (nonzero) digits is 140, while the sum is 19.

The square root of 5110147 is about 2260.5634253433. The cubic root of 5110147 is about 172.2441435541.

Subtracting 5110147 from its reverse (7410115), we obtain a cube (2299968 = 1323).

The spelling of 5110147 in words is "five million, one hundred ten thousand, one hundred forty-seven".

Divisors: 1 7 730021 5110147