Base | Representation |
---|---|
bin | 101111100110000100… |
… | …011010000001111011 |
3 | 11212220120020101102011 |
4 | 233212010122001323 |
5 | 1314130231231011 |
6 | 35251015550351 |
7 | 3456263360050 |
oct | 574604320173 |
9 | 155816211364 |
10 | 51104555131 |
11 | 1a745209733 |
12 | 9aa298b3b7 |
13 | 4a85856b46 |
14 | 268b2d7027 |
15 | 14e182a621 |
hex | be611a07b |
51104555131 has 16 divisors (see below), whose sum is σ = 60454065600. Its totient is φ = 42269004288.
The previous prime is 51104555069. The next prime is 51104555153. The reversal of 51104555131 is 13155540115.
It is a happy number.
51104555131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-51104555131 is a prime.
It is a super-5 number, since 5×511045551315 (a number of 55 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51104555093 and 51104555102.
It is not an unprimeable number, because it can be changed into a prime (51104555191) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 284055 + ... + 427663.
It is an arithmetic number, because the mean of its divisors is an integer number (3778379100).
Almost surely, 251104555131 is an apocalyptic number.
51104555131 is a deficient number, since it is larger than the sum of its proper divisors (9349510469).
51104555131 is a wasteful number, since it uses less digits than its factorization.
51104555131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145398.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 51104555131 in words is "fifty-one billion, one hundred four million, five hundred fifty-five thousand, one hundred thirty-one".
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