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BaseRepresentation
bin1001100001011011…
…00101000110100011
3111012021112210100211
410300231211012203
540432212101430
62203140354551
7240454112440
oct46055450643
914167483324
105112222115
112193797160
12ba80a5a57
13636191500
14366d549c7
151edc2272a
hex130b651a3

5112222115 has 48 divisors (see below), whose sum is σ = 8282117376. Its totient is φ = 2941660800.

The previous prime is 5112222103. The next prime is 5112222131.

It is a happy number.

5112222115 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 5112222115 - 25 = 5112222083 is a prime.

It is a super-2 number, since 2×51122221152 = 52269629906190146450, which contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 25780 + ... + 104350.

It is an arithmetic number, because the mean of its divisors is an integer number (172544112).

Almost surely, 25112222115 is an apocalyptic number.

5112222115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

5112222115 is a deficient number, since it is larger than the sum of its proper divisors (3169895261).

5112222115 is a wasteful number, since it uses less digits than its factorization.

5112222115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78620 (or 78607 counting only the distinct ones).

The product of its digits is 400, while the sum is 22.

The square root of 5112222115 is about 71499.8049997341. The cubic root of 5112222115 is about 1722.6745521460.

It can be divided in two parts, 51122 and 22115, that added together give a palindrome (73237).

The spelling of 5112222115 in words is "five billion, one hundred twelve million, two hundred twenty-two thousand, one hundred fifteen".