Base | Representation |
---|---|
bin | 100101001100100101011… |
… | …1100010111111011010111 |
3 | 200002201122202221220222011 |
4 | 1022121022330113323113 |
5 | 1132224411204012441 |
6 | 14512313234245051 |
7 | 1035230530416301 |
oct | 112311274277327 |
9 | 20081582856864 |
10 | 5112268422871 |
11 | 16a1112280315 |
12 | 6a6960426787 |
13 | 2b111452b50c |
14 | 139613d38971 |
15 | 8ceada4e581 |
hex | 4a64af17ed7 |
5112268422871 has 4 divisors (see below), whose sum is σ = 5126750770032. Its totient is φ = 5097786075712.
The previous prime is 5112268422839. The next prime is 5112268422913. The reversal of 5112268422871 is 1782248622115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5112268422871 - 25 = 5112268422839 is a prime.
It is a super-2 number, since 2×51122684228712 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112268222871) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7241173051 + ... + 7241173756.
It is an arithmetic number, because the mean of its divisors is an integer number (1281687692508).
Almost surely, 25112268422871 is an apocalyptic number.
5112268422871 is a deficient number, since it is larger than the sum of its proper divisors (14482347161).
5112268422871 is a wasteful number, since it uses less digits than its factorization.
5112268422871 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14482347160.
The product of its digits is 860160, while the sum is 49.
The spelling of 5112268422871 in words is "five trillion, one hundred twelve billion, two hundred sixty-eight million, four hundred twenty-two thousand, eight hundred seventy-one".
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