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BaseRepresentation
bin1001111111001
321000101
41033321
5130423
635401
720623
oct11771
97011
105113
113929
122b61
132434
141c13
hex13f9

5113 has 2 divisors, whose sum is σ = 5114. Its totient is φ = 5112.

The previous prime is 5107. The next prime is 5119. The reversal of 5113 is 3115.

5113 is nontrivially palindromic in base 2.

It is a balanced prime because it is at equal distance from previous prime (5107) and next prime (5119).

It can be written as a sum of positive squares in only one way, i.e., 2809 + 2304 = 53^2 + 48^2 .

5113 is a truncatable prime.

It is a cyclic number.

It is not a de Polignac number, because 5113 - 25 = 5081 is a prime.

It is a super-2 number, since 2×51132 = 52285538, which contains 22 as substring.

It is the 72-nd Hogben number.

It is a plaindrome in base 15.

It is a self number, because there is not a number n which added to its sum of digits gives 5113.

It is not a weakly prime, because it can be changed into another prime (5119) by changing a digit.

It is a nontrivial repunit in base 71.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556 + 2557.

It is an arithmetic number, because the mean of its divisors is an integer number (2557).

25113 is an apocalyptic number.

It is an amenable number.

5113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113 is an equidigital number, since it uses as much as digits as its factorization.

5113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15, while the sum is 10.

The square root of 5113 is about 71.5052445629. The cubic root of 5113 is about 17.2276192281.

Adding to 5113 its reverse (3115), we get a palindrome (8228).

It can be divided in two parts, 51 and 13, that added together give a 6-th power (64 = 26).

The spelling of 5113 in words is "five thousand, one hundred thirteen".