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5113433 = 13279383
BaseRepresentation
bin10011100000011001011001
3100121210022102
4103200121121
52302112213
6301333145
761314653
oct23403131
910553272
105113433
112982886
1218671b5
1310a0600
149716d3
156b0158
hex4e0659

5113433 has 12 divisors (see below), whose sum is σ = 5621760. Its totient is φ = 4648176.

The previous prime is 5113417. The next prime is 5113441. The reversal of 5113433 is 3343115.

It is a happy number.

5113433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 5113433 - 24 = 5113417 is a prime.

It is a super-2 number, since 2×51134332 = 52294394090978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5113403) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13160 + ... + 13542.

It is an arithmetic number, because the mean of its divisors is an integer number (468480).

Almost surely, 25113433 is an apocalyptic number.

It is an amenable number.

5113433 is a deficient number, since it is larger than the sum of its proper divisors (508327).

5113433 is a wasteful number, since it uses less digits than its factorization.

5113433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 488 (or 475 counting only the distinct ones).

The product of its digits is 540, while the sum is 20.

The square root of 5113433 is about 2261.2901184943. The cubic root of 5113433 is about 172.2810552764.

Adding to 5113433 its reverse (3343115), we get a palindrome (8456548).

The spelling of 5113433 in words is "five million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 13 79 169 383 1027 4979 13351 30257 64727 393341 5113433