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5113441 is a prime number
BaseRepresentation
bin10011100000011001100001
3100121210022201
4103200121201
52302112231
6301333201
761314664
oct23403141
910553281
105113441
112982893
121867201
1310a0608
149716db
156b0161
hex4e0661

5113441 has 2 divisors, whose sum is σ = 5113442. Its totient is φ = 5113440.

The previous prime is 5113417. The next prime is 5113477. The reversal of 5113441 is 1443115.

5113441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3721041 + 1392400 = 1929^2 + 1180^2 .

It is a cyclic number.

It is not a de Polignac number, because 5113441 - 29 = 5112929 is a prime.

It is a super-2 number, since 2×51134412 = 52294557720962, which contains 22 as substring.

It is an Ulam number.

It is not a weakly prime, because it can be changed into another prime (5123441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556720 + 2556721.

It is an arithmetic number, because the mean of its divisors is an integer number (2556721).

Almost surely, 25113441 is an apocalyptic number.

It is an amenable number.

5113441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113441 is an equidigital number, since it uses as much as digits as its factorization.

5113441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 240, while the sum is 19.

The square root of 5113441 is about 2261.2918873953. The cubic root of 5113441 is about 172.2811451213.

Adding to 5113441 its reverse (1443115), we get a palindrome (6556556).

The spelling of 5113441 in words is "five million, one hundred thirteen thousand, four hundred forty-one".