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511414124041 = 1313903924611
BaseRepresentation
bin1110111000100101010…
…10000011111000001001
31210220001022220021212101
413130102222003320021
531334334003432131
61030535043313401
751643214221042
oct7342252037011
91726038807771
10511414124041
11187986a38867
128314767b861
13392c2ac0722
141aa770d38c9
15d482c25c61
hex7712a83e09

511414124041 has 4 divisors (see below), whose sum is σ = 515318048784. Its totient is φ = 507510199300.

The previous prime is 511414124021. The next prime is 511414124063. The reversal of 511414124041 is 140421414115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 511414124041 - 211 = 511414121993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (511414124021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1951962175 + ... + 1951962436.

It is an arithmetic number, because the mean of its divisors is an integer number (128829512196).

Almost surely, 2511414124041 is an apocalyptic number.

It is an amenable number.

511414124041 is a deficient number, since it is larger than the sum of its proper divisors (3903924743).

511414124041 is a wasteful number, since it uses less digits than its factorization.

511414124041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3903924742.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 511414124041 its reverse (140421414115), we get a palindrome (651835538156).

The spelling of 511414124041 in words is "five hundred eleven billion, four hundred fourteen million, one hundred twenty-four thousand, forty-one".

Divisors: 1 131 3903924611 511414124041