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5114312132 = 221278578033
BaseRepresentation
bin1001100001101011…
…00011010111000100
3111012102110222022212
410300311203113010
540433230442012
62203253242552
7240510635666
oct46065432704
914172428285
105114312132
112194994446
12ba8933458
136367438c7
1436733a536
151eded6b22
hex130d635c4

5114312132 has 6 divisors (see below), whose sum is σ = 8950046238. Its totient is φ = 2557156064.

The previous prime is 5114312111. The next prime is 5114312143. The reversal of 5114312132 is 2312134115.

It can be written as a sum of positive squares in only one way, i.e., 4573005376 + 541306756 = 67624^2 + 23266^2 .

It is a junction number, because it is equal to n+sod(n) for n = 5114312098 and 5114312107.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 639289013 + ... + 639289020.

It is an arithmetic number, because the mean of its divisors is an integer number (1491674373).

Almost surely, 25114312132 is an apocalyptic number.

It is an amenable number.

5114312132 is a deficient number, since it is larger than the sum of its proper divisors (3835734106).

5114312132 is a wasteful number, since it uses less digits than its factorization.

5114312132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1278578037 (or 1278578035 counting only the distinct ones).

The product of its digits is 720, while the sum is 23.

The square root of 5114312132 is about 71514.4190495875. The cubic root of 5114312132 is about 1722.9092790729.

Adding to 5114312132 its reverse (2312134115), we get a palindrome (7426446247).

The spelling of 5114312132 in words is "five billion, one hundred fourteen million, three hundred twelve thousand, one hundred thirty-two".

Divisors: 1 2 4 1278578033 2557156066 5114312132