Base | Representation |
---|---|
bin | 110000010110101110… |
… | …110000011010110011 |
3 | 11222000110110012210221 |
4 | 300112232300122303 |
5 | 1322313231311001 |
6 | 35504022233511 |
7 | 3515435622463 |
oct | 602656603263 |
9 | 158013405727 |
10 | 51920963251 |
11 | 20024037193 |
12 | a090285897 |
13 | 4b85a33281 |
14 | 27278d3ba3 |
15 | 153d3441a1 |
hex | c16bb06b3 |
51920963251 has 2 divisors, whose sum is σ = 51920963252. Its totient is φ = 51920963250.
The previous prime is 51920963231. The next prime is 51920963267. The reversal of 51920963251 is 15236902915.
51920963251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51920963251 - 27 = 51920963123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51920963198 and 51920963207.
It is not a weakly prime, because it can be changed into another prime (51920963231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25960481625 + 25960481626.
It is an arithmetic number, because the mean of its divisors is an integer number (25960481626).
Almost surely, 251920963251 is an apocalyptic number.
51920963251 is a deficient number, since it is larger than the sum of its proper divisors (1).
51920963251 is an equidigital number, since it uses as much as digits as its factorization.
51920963251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 43.
The spelling of 51920963251 in words is "fifty-one billion, nine hundred twenty million, nine hundred sixty-three thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •